(1+2k^2)+(2k^2-3)=

Solution for (1+2k^2)+(2k^2-3)= equation:

Simplifying
(1 + 2k2) + (2k2 + -3) = 0

Remove parenthesis around (1 + 2k2)
1 + 2k2 + (2k2 + -3) = 0

Reorder the terms:
1 + 2k2 + (-3 + 2k2) = 0

Remove parenthesis around (-3 + 2k2)
1 + 2k2 + -3 + 2k2 = 0

Reorder the terms:
1 + -3 + 2k2 + 2k2 = 0

Combine like terms: 1 + -3 = -2
-2 + 2k2 + 2k2 = 0

Combine like terms: 2k2 + 2k2 = 4k2
-2 + 4k2 = 0

Solving
-2 + 4k2 = 0

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 4k2 = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 4k2 = 0 + 2
4k2 = 0 + 2

Combine like terms: 0 + 2 = 2
4k2 = 2

Divide each side by '4'.
k2 = 0.5

Simplifying
k2 = 0.5

Take the square root of each side:
k = {-0.707106781, 0.707106781}